Date: Mon, 11 Mar 2002 09:56:17 -0600
Reply-To: Alex Shackman <shackman@psyphw.psych.wisc.edu>
Sender: "SPSSX(r) Discussion" <SPSSX-L@LISTSERV.UGA.EDU>
From: Alex Shackman <shackman@psyphw.psych.wisc.edu>
Subject: [kkhoie@USA.COM: Normalizing skewed distributions using SPSS 6.0]
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The appropriate transformation will depend upon the magnitude of the skew.
In order of "strength" (a la J. Tukey), from minimal transforming to
maximal:
(x)^.75
(x)^.66 {2/3 root}
sqrt(x) = (x)^.5
(x)^.33 {cube root}
(x)^.25
log10(x) = ln(x)
1/x {reciprocal transformation}
Occasionally, more exotic transforms are useful. For example,
1/(sqrt(x)) or log(log(x)).
NB: you may need to add a constant to x to maintain the appropriate
rank ordering of cell means, as when some observations are negatively
signed.
**Always check the rank order of cell means after transformation**
To choose the "optimal" transformation, the skewness, kurtosis and
homogeneity of variances should be compared.
Best,
Alex Shackman
----- Forwarded message from Kathy Khoie <kkhoie@USA.COM> -----
Newsgroups: bit.listserv.spssx-l
Date: Mon, 11 Mar 2002 02:30:43 -0500
Reply-To: Kathy Khoie <kkhoie@USA.COM>
From: Kathy Khoie <kkhoie@USA.COM>
Subject: Normalizing skewed distributions using SPSS 6.0
To: SPSSX-L@LISTSERV.UGA.EDU
Hi,
I'm new to the list. Could not find a FAQ or archive. Need some input on
normalizing skewed distributions. Any guidance on this topic will be
appreciated,
Regards,
Kathy
----- End forwarded message -----