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Date:         Fri, 19 Apr 2002 06:51:14 -0500
Reply-To:     "Marks, Jim" <jim.marks@lodgenet.com>
Sender:       "SPSSX(r) Discussion" <SPSSX-L@LISTSERV.UGA.EDU>
From:         "Marks, Jim" <jim.marks@lodgenet.com>
Subject:      Re: Quick syntax question (Was: NPAR for 2-way ANOVA? (last chapt
              er))
Content-Type: text/plain; charset="iso-8859-1"

The statement (facta=2) is evaluated as true or false, with true=1 and false=0.

When facta eq 2, group = factb + facta*1 = factb + 2

When fact ne 2, group = factb + facta*0 = factb HTH

Jim Marks Market Analyst LodgeNet Entertainment Corporation 605.988.1616

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-----Original Message----- From: D.R. Wahlgren [mailto:dwahlgren@sdsuf.projects.sdsu.edu] Sent: Thursday, April 18, 2002 2:45 PM To: SPSSX-L@LISTSERV.UGA.EDU Subject: Quick syntax question (Was: NPAR for 2-way ANOVA? (last chapter))

Hi Marta!

At 5:01 PM +0200 4/17/02, Asesoría Bioestadística wrote: > > >COMPUTE group= factb +facta*(facta=2).

Thanks for your help! I have quick question on the above syntax. My background in syntax is limited, so I hope this isn't ridiculously simple.

My question is about the expression (facta=2) above. You are multiplying the value of facta by that expression, but I would expect either a variable or a value in the ( ), not a "variable=value" expression. Would you please explain what this syntax does?

Much thanks!

_dennis


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