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Date:         Thu, 6 Mar 2003 03:03:35 GMT
Sender:       "SAS(r) Discussion" <SAS-L@LISTSERV.UGA.EDU>
From:         Roger Lustig <trovato@BELLATLANTIC.NET>
Subject:      Re: Address match
Content-Type: text/plain; charset=us-ascii; format=flowed

Dear Chandra: Try this.

***** Add a sequence number within each ID group; ***** Assume that BASE is sorted by ID already; data numbered; do seq=1 by 1 until (; set base; output; end; run;

***** Compare each to each within ID groups; proc sql; create table compared as select a.*, b.b_seq, b.b_address, /* SPEDIS is not symmetrical. */ /* Try different metrics depending on your problem. */ spedis(a.a_address,b.b_address) as spedis_ab, spedis(b.b_address,a.a_address) as spedis_ba /*Insert other variables of your choice here */ from numbered a (rename=(address=a_address seq=a_seq)), numbered b (rename=(address=b_address seq=b_seq)) where and /* Eliminate duplication */ a.a_seq < b.b_seq /* Any other ordering would do fine too */ order by,max(spedis_ab,spedis_ba) ; quit; proc print noobs; by ID; run; Best,

Roger Lustig

chandra kalisetty wrote: > Hello All > > I am trying to da an address match on my data. My data looks as follows. > > id address > 1 123 main street > 1 123 main street > 1 23 state street > 2 345 south blvd > 2 78 north street > 3 89 royal drive > 3 89 royal drive > > I want to compare the address with in the same id. The problem is hw can I > compare first address with the second address. How can I look at the second > address. Can I use arrays? also I don't know how many addreses are there > for > the same ID. To compare addresses I can use "SPEDIS" function. But, How to > lok at the second observation. > > Any help is greatly appreciated > Thanks > Sekhar > > > > _________________________________________________________________ > Cricket World Cup 2003- News, Views and Match Reports. >

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