Date: Tue, 29 Jul 2003 15:16:14 -0400
Reply-To: Art@DrKendall.org
Sender: "SPSSX(r) Discussion" <SPSSX-L@LISTSERV.UGA.EDU>
From: "Arthur J. Kendall" <Art@DrKendall.org>
Organization: Social Research Consultants
Subject: Re: Measures of Central Tendency from Categorical data
Content-Type: text/plain; charset=ISO-8859-1; format=flowed
I have been using SPSS since 1972, and still learn new things.
Art
Asesorma Bioestadmstica wrote:
> Hi:
>
> "Arthur J. Kendall" ha escrito:
>
>
>>data list list/ name (a5) mid freq exten.
>>begin data
>>18-20 19 12 228
>>21-23 22 7 154
>>24-26 25 8 200
>>27-29 28 9 252
>>30-32 31 3 93
>>33-35 34 1 34
>>end data.
>>list.
>>weight by freq.
>>frequencies vars= mid /statistics=all/hbar.
>
>
> If data are interval midpoints, then add "/grouped= mid" to the syntax:
>
> data list list/ name (a5) mid freq exten.
> begin data
> 18-20 19 12 228
> 21-23 22 7 154
> 24-26 25 8 200
> 27-29 28 9 252
> 30-32 31 3 93
> 33-35 34 1 34
> end data.
> list.
> weight by freq.
>
> frequencies vars= mid /statistics=all /hbar /GROUPED=mid.
>
> This will give you the interpolated median value.
>
> HTH
>
> Marta Garcia-Granero
>
>
>>
>>Valdiserri, Colin wrote:
>>
>>>Zachary,
>>>
>>>Actually there are statistical formulas to obtain such results from categorical data. One I am familiar with is the following with sample data. But I do know there are others out there which tackle the issue where the category anchors are "less than ..." and "greater than..." That is the one I am trying to find.
>>>
>>>Solution for Mean
>>>
>>>X MP f MP* f
>>>18-20 19 12 228
>>>21-23 22 7 154
>>>24-26 25 8 200
>>>27-29 28 9 252
>>>30-32 31 3 93
>>>33-35 34 1 34
>>> N=40 ? MPf=961
>>>
>>>X = ?Xf = 24.05
>>> N
>>>
>>>Colin M. Valdiserri
>>>Associate Consumer Scientist
>>>The Calphalon Group
>>>(419) 662-2378 - Office
>>>(419) 661-0223 - Fax
>>>Colin.Valdiserri@calphalon.com
>>>
>>>
>>>-----Original Message-----
>>>From: Feinstein, Zachary [mailto:ZFeinstein@HarrisInteractive.com]
>>>Sent: Tuesday, July 29, 2003 10:48 AM
>>>To: Valdiserri, Colin; SPSSX-L@LISTSERV.UGA.EDU
>>>Subject: RE: Measures of Central Tendency from Categorical data
>>>
>>>
>>>You cannot get a mean or median from categorical data. [I guess you could,
>>>but it would be meaningless.] Means and medians are for data that are
>>>quantitative or have some kind of numerical scale. The best measure of
>>>central tendency for categorical data is a mode- the most often occurring
>>>response. There are plenty of advanced statistical techniques that work
>>>with categorical data where you would obtain the mean or median of some
>>>other measures associated with it, but that's a whole other ballgame.
>>>
>>>Zachary
>>>
>>>-----Original Message-----
>>>From: Valdiserri, Colin [mailto:Colin.Valdiserri@calphalon.com]
>>>Sent: Tuesday, July 29, 2003 9:11 AM
>>>To: SPSSX-L@LISTSERV.UGA.EDU
>>>Subject: Measures of Central Tendency from Categorical data
>>>
>>>
>>>Hello All,
>>>
>>>Does anyone have a formula to obtain a mean and median from categorical
>>>data, or can you refer me to literature that explains this probelm.
>>>
>>>Colin M. Valdiserri
>>>Associate Consumer Scientist
>>>The Calphalon Group
>>>(419) 662-2378 - Office
>>>(419) 661-0223 - Fax
>>>Colin.Valdiserri@calphalon.com
>>>
>>>
>>>
>>>
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>>>
>>>
>>>
>>>THIS MESSAGE MAY CONTAIN INFORMATION THAT IS CONFIDENTIAL AND/OR PROTECTED BY LAW. IF THE READER OF THIS MESSAGE IS NOT THE INTENDED RECIPIENT, YOU ARE HEREBY NOTIFIED THAT ANY DISSEMINATION, DISTRIBUTION, COPYING OR COMMUNICATION OF THIS MESSAGE IS STRICTLY PROHIBITED. IF YOU HAVE RECEIVED THIS COMMUNICATION IN ERROR, PLEASE CONTACT THE SENDER IMMEDIATELY AND DELETE THE MESSAGE. PLEASE NOTE THAT ALTHOUGH WE WILL TAKE ALL COMMERCIALLY REASONABLE EFFORTS
>>>TO PREVENT VIRUSES FROM BEING TRANSMITTED FROM OUR
>>>SYSTEMS, IT IS THE RESPONSIBILITY OF THE RECIPIENT TO CHECK FOR AND PREVENT ADVERSE ACTION BY VIRUSES ON ITS OWN SYSTEMS .
>>>
>>
>
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