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Date:         Thu, 11 Mar 2004 13:37:33 -0600
Reply-To:     Dewen Hou <Dewen.Hou@BLOCKBUSTER.COM>
Sender:       "SAS(r) Discussion" <SAS-L@LISTSERV.UGA.EDU>
From:         Dewen Hou <Dewen.Hou@BLOCKBUSTER.COM>
Subject:      Super Size Dataset from Cartesian Join
Comments: To: SAS-L@LISTSERV.VT.EDU
Content-type: text/plain; charset=US-ASCII

Dear All,

I have to use a Cartesian join on a dataset, which represents a grid area, to set up a look-up matrix table for each cell in the grid against all other cells in the same grid file. Then I calculate the distance among all the cells, just to keep those with distance smaller than 1 mile. Please look at the codes below.

The problem is if the nop.newgrid dataset has 60,000 cells, the Cartesian join table nop.dist_matrix_all will have 3.6 billion records (60,000 X 60,000). I saw a temp dataset file as big as 78 GB in my local drive. None of my machines can reach the final nop.dist_matrix_all dataset.

So, is there a way to work around this?

Thank you so much!

David Hou

/********************************************************************/ /*Create a new distance for all &maxcells against all cells*/ /*******************************************************************/ proc sql; create table nop.dist_matrix_all as select a.cellid as cellid_m, a.X as X1, a.Y as Y1, b.cellid as cellid_all, b.X as X2, b.Y as Y2 from nop.newgrid. a, nop.newgrid. b; quit;

/********************************************************************/ /*Calculate distance */ /********************************************************************/ data nop.dist_matrix_all; set nop.dist_matrix_all; iLon1 = X1*3.14159/180; iLon2 = X2*3.14159/180; iLat1 = Y1*3.14159/180; iLat2 = Y2*3.14159/180;

iDiffLon = iLon2 - iLon1; iDiffLat = iLat2 - iLat1;

minNum = sqrt(sin(iDifflat/2)*sin(iDifflat/2) + cos(iLat1)* cos(iLat2)*sin(iDiffLon/2)*sin(iDiffLon/2)); result = 2*ArSin(min(1, minNum))*6370997; distance = result/1609.344; if distance < 1 and distance > 0; Keep cellid_m cellid_all distance; run;


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