Date:         Wed, 22 Sep 2004 11:14:28 +0200
Reply-To:     lucameyer@tiscali.it
Sender:       "SPSSX(r) Discussion" <SPSSX-L@LISTSERV.UGA.EDU>
From:         Luca Meyer <lucameyer@tiscali.it>
Organization: Luca Meyer
Subject:      Mod(x,y) specification - why it does work this way?
In-Reply-To:  <41485B2D.6080804@verizon.net>
Content-Type: text/plain; charset="us-ascii"

Dear Art,

I am studying the following spss code you post on the list (this one is
from a mail of Wednesday 15th):

>
> new file.
> input program.
> string spec (A30).
> loop #v  = 1 to 5.
> do if mod(#v,20) eq 1.
> write outfile = 'd:\project\longway.sps'
>  / 'crosstabs' .
> end if.
> compute spec = concat(' /v1_', ltrim(string(#v,f3)),' by
> v2_',ltrim(string(#v,f3))). write outfile =
> 'd:\project\longway.sps'  / spec . do if mod(#v,20) eq 0 or
> #v eq 5. write outfile = 'd:\project\longway.sps'
>  / '   /cells = columns .' .
> end if.
> end loop.
> end case.
> end loop.
> end file.
> end input program.
> execute.
>

I am having hard time to understand how the MOD(#v,20) command you
included in the syntax performs. As far as I understand from the SPSS
v12 guide, the MOD(X,Y) command should return the reminded of the
division of X by Y.

Now, if I write out the results you imply in the syntax they are:

#v=1 mod=1/20=05
#v=2 mod=2/20=1
#v=3 mod=3/20=15
#v=4 mod=4/20=2
#v=5 mod=4/20=25

So, from the

> do if mod(#v,20) eq 1.
> write outfile = 'd:\project\longway.sps'
>  / 'crosstabs' .
> end if.

I should actually expect that the outfile would be written starting from
#v=2 and not from #v=1 - like it happens - or I am making a mistake
somewhere?

Thanks for clarifying that point for me.

Luca

Mr. Luca Meyer
Consumer research advisor: http://www.lucameyer.com/en/
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