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Date:         Thu, 25 Nov 2004 20:46:40 -0500
Reply-To:     "Richard A. DeVenezia" <radevenz@IX.NETCOM.COM>
Sender:       "SAS(r) Discussion" <SAS-L@LISTSERV.UGA.EDU>
From:         "Richard A. DeVenezia" <radevenz@IX.NETCOM.COM>
Subject:      Re: random partitions

Chang Y. Chung wrote: > On Thu, 25 Nov 2004 14:21:53 -0200, jlamack <jlamack@BOL.COM.BR> > wrote: > >> Dear all, I have a sas data set with 40 observations. >> I would like to get 8 random partitions of size 5 of this sas data >> set. Please, How can I do this?? > > A sort-less solution that requires 9's call ranperm. :-) >

A v9 solution using a hash and hiter. Not sure if ordered qualifies as sortless.

%let seed = 0;

data parts;

declare hash h (ordered:'a'); h.defineKey ('x'); h.defineData ('rowId'); h.defineDone ();

call missing (x, rowId, groupId);

do rowid = 1 to 40; x = ranuni (&seed); h.add (); end;

declare hiter hi ('h'); do _n_ = 0 by 1 while (; groupId = floor (_n_/5); output; end;


drop x; run;

-- Richard A. DeVenezia

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