Hi Simon,

The following illustrates how to create a string variable containing a TAB character. That variable can then be used in you ANY function.

DATA LIST LIST /str1(A2). BEGIN DATA 79 /* letter O */ 80 /* letter P */ 09 /* TAB character */ END DATA.

STRING char(A1) str25(A25). COMPUTE char=STRING(NUMBER(str1,N2),PIB1). COMPUTE str25=CONCAT("---",char,"==="). LIST str25.

HTH

Raynald Levesque Raynald@spsstools.net Visit my SPSS site: http://www.spsstools.net

-----Original Message----- From: SPSSX(r) Discussion [mailto:SPSSX-L@LISTSERV.UGA.EDU]On Behalf Of Simon Freidin Sent: January 16, 2005 6:05 PM To: SPSSX-L@LISTSERV.UGA.EDU Subject: tabs in strings

Anyone know how to identify tabs in strings?

I want to identify a tab delimiter in the following expression:

do if any(delim,',',' ','/',"'",'"','(','*','-','+','>','<','=',' ').

delim is a single character. The last item in the list is a tab-in-single-quotes but spss doesn't recognise it.

tia Simon

Research Database Manager and Analyst Melbourne Institute of Applied Economic and Social Research The University of Melbourne Melbourne VIC 3010 Australia New Tel: (03) 8344 2085 New Fax: (03) 8344 2111 http://www.melbourneinstitute.com/hilda/