Edward

DATA LIST FREE /id (f8.0) date (date10). BEGIN DATA 1 11-12-2001 1 21-12-2001 1 30-12-2001 2 10-1-2000 2 12-1-2000 2 15-2-2000 2 20-3-2000 2 26-4-2000 END DATA.

AGGREGATE OUTFILE = * /BREAK id /start = MIN(date) /end = MAX(date).

COMPUTE days = (end - start)/ 86400. FORMAT days (f8.0). LIST id days.

--jim

-----Original Message----- From: SPSSX(r) Discussion [mailto:SPSSX-L@LISTSERV.UGA.EDU] On Behalf Of Edward Boadi Sent: Tuesday, September 12, 2006 8:10 AM To: SPSSX-L@LISTSERV.UGA.EDU Subject: Re: calculations between rows solved

Paul, I am interested in knowing (syntax) how that was done. Regards. Edward.

-----Original Message----- From: SPSSX(r) Discussion [mailto:SPSSX-L@LISTSERV.UGA.EDU]On Behalf Of Paul Mcgeoghan Sent: Tuesday, September 12, 2006 6:03 AM To: SPSSX-L@LISTSERV.UGA.EDU Subject: calculations between rows solved

Figured it out using Data Aggregate, I can specify the 1st row and the last row and create a new aggregated dataset from that where I can then compute the difference between the 2 dates.

Hi,

I have a customer with data as follows: ID Date 1 11-DEC-2001 1 21-DEC-2001 1 30-DEC-2001 2 10-JAN-2000 2 12-JAN-2000 2 15-FEB-2000 2 20-MAR-2000 2 26-APR-2000

He wants to have: ID Days 1 19 2 107

What is best way to do this? Thanks, Paul

================== Paul McGeoghan, Application support specialist (Statistics and Databases), University Infrastructure Group (UIG), Information Services, Cardiff University. Tel. 02920 (875035).