Date:         Mon, 22 Jan 2007 13:37:33 +0000
Reply-To:     toby dunn <tobydunn@HOTMAIL.COM>
Sender:       "SAS(r) Discussion" <SAS-L@LISTSERV.UGA.EDU>
From:         toby dunn <tobydunn@HOTMAIL.COM>
Subject:      Re: FILE PROPERTIES
Comments: To: praveencbharadwaj@GMAIL.COM
In-Reply-To:  <1169472174.623137.251160@v45g2000cwv.googlegroups.com>
Content-Type: text/plain; format=flowed

Well Sunny we do this for free so dont get too pushy on the time line.

Next all you need is:

Libname Test "/ABC/XYZ" ;

Proc SQL ;
Create Table DataInfo As
Select *
  From Dictionary.Tables ;
  Where Libname = 'TEST' ;
Quit ;

Proc Print
Data = Datainfo ;
Run ;



Toby Dunn

To sensible men, every day is a day of reckoning. ~John W. Gardner

The important thing is this: To be able at any moment to sacrifice that
which we are for what we could become. ~Charles DuBois

Don't get your knickers in a knot. Nothing is solved and it just makes you
walk funny. ~Kathryn Carpenter






From: sunny <praveencbharadwaj@GMAIL.COM>
Reply-To: sunny <praveencbharadwaj@GMAIL.COM>
To: SAS-L@LISTSERV.UGA.EDU
Subject: FILE PROPERTIES
Date: Mon, 22 Jan 2007 05:22:54 -0800

data diropts;

length optname $ 12 optval $ 40;

keep optname optval memcount;

rc=filename("mydir1" ,"F:\sourcetemp\praventest");

did=dopen("mydir1");

numopts=doptnum(did);

do i = 1 to  numopts;

optname=doptname(did,i);

memcount=dnum(did);

optval=dinfo(did,optname);

output;

end;

run;


I  used the cod  to know the directoty name and number of filesin it.
But to know the created  date  and the modified date .Please help me in
my code.





Details:

I had a directory and i have the files in it .
I need to know the name of the files and the created  date  and the
modified date .
For this i can know the number of files which are uploading ..
Please help me as quickly as possible.

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