On Thu, 18 Oct 2007 09:05:41 -0700, BJMurphy <murphy.ben@GMAIL.COM> wrote:

>Hi All, > >I want to figure out whether today is the first business day of the >month in my code so that if I run the job every day, it automatically >handles certain tasks on the first business day of the month. Assume >that weekends and US federal/bank holidays are the only non-business >days. I have this code that works within a data step and takes a SAS >date variable (date) and determines if it is a holiday or not: > > mmdd = substr(put(date,mmddyy6.),1,4); > if (weekday(date) in (1,7)) then date_type = 'w'; /* weekend */ > else if > (mmdd in ('0101','0704','1111','1225')) or > (weekday(date) = 2 and > ((mmdd in ('0102','0705','1112','1226') or > '0115' <= mmdd <= '0121' or > '0215' <= mmdd <= '0221' or > '0525' <= mmdd <= '0531' or > '0901' <= mmdd <= '0907' or > '1008' <= mmdd <= '1014'))) or > (weekday(date) = 5 and '1122' <= mmdd <= '1128') > then date_type = 'h'; /* holiday */ > else date_type = 'b'; /* business day */ > >I can't decide the best way to figure out whether today was the first >business day or not. It seems like I could either populate a data set >with the last 31 days and test each one in succession, setting this >date_type appropriately, but I feel like this sort of inelegant brute >force method has some superior alternative. > >Any suggestions would be great. > >Thanks, >Ben

Loop through the days from say 1 Jan. 1900 to 31 December 2099 (or some other interval which is assuredly a superset of your actual days of interest) and populate a data set with yes/no flags indicating whether each is or is not first business day. Create a format from this table.