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Date:         Wed, 2 Jan 2008 15:14:51 -0600
Reply-To:     "Swank, Paul R" <Paul.R.Swank@uth.tmc.edu>
Sender:       "SPSSX(r) Discussion" <SPSSX-L@LISTSERV.UGA.EDU>
From:         "Swank, Paul R" <Paul.R.Swank@uth.tmc.edu>
Subject:      Re: Independent Sample T-Test (UNCLASSIFIED)
Comments: To: "Sparling, Steven J MAJ MIL USA SA"
          <steven.j.sparling@US.ARMY.MIL>
In-Reply-To:  <40E77EB8B6740545B9FFF0B153711F9E08E423@belv010be000004.nae.ds.army.mil>
Content-Type: text/plain; charset="us-ascii"

Check that Mu1 is truly less than Mu2 and divide the two tailed p by 2. If Mu1 < mu2 and the p given is .054, then the one tailed p is .054/2 = .027.

Paul R. Swank, Ph.D. Professor and Director of Research Children's Learning Institute University of Texas Health Science Center - Houston

-----Original Message----- From: SPSSX(r) Discussion [mailto:SPSSX-L@LISTSERV.UGA.EDU] On Behalf Of Sparling, Steven J MAJ MIL USA SA Sent: Wednesday, January 02, 2008 12:24 PM To: SPSSX-L@LISTSERV.UGA.EDU Subject: Independent Sample T-Test (UNCLASSIFIED)

Classification: UNCLASSIFIED Caveats: NONE

I want to do a T-test on two groups. Group 1 receives a treatment, group 2 does not.

The standard null hypothesis applies: MU1 = MU2 My alternative hypothesis is MU1 < MU2.

The default alternative in SPSS is MU1 not equal to MU2, and provides 2 sided significance.

Is there a way to specify the strictly less than condition in my alternative hypothesis?

Steve

Classification: UNCLASSIFIED Caveats: NONE

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