Date: Wed, 2 Jan 2008 15:14:51 -0600
Reply-To: "Swank, Paul R" <Paul.R.Swank@uth.tmc.edu>
Sender: "SPSSX(r) Discussion" <SPSSX-L@LISTSERV.UGA.EDU>
From: "Swank, Paul R" <Paul.R.Swank@uth.tmc.edu>
Subject: Re: Independent Sample T-Test (UNCLASSIFIED)
In-Reply-To: <40E77EB8B6740545B9FFF0B153711F9E08E423@belv010be000004.nae.ds.army.mil>
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Check that Mu1 is truly less than Mu2 and divide the two tailed p by 2.
If Mu1 < mu2 and the p given is .054, then the one tailed p is .054/2 =
.027.
Paul R. Swank, Ph.D.
Professor and Director of Research
Children's Learning Institute
University of Texas Health Science Center - Houston
-----Original Message-----
From: SPSSX(r) Discussion [mailto:SPSSX-L@LISTSERV.UGA.EDU] On Behalf Of
Sparling, Steven J MAJ MIL USA SA
Sent: Wednesday, January 02, 2008 12:24 PM
To: SPSSX-L@LISTSERV.UGA.EDU
Subject: Independent Sample T-Test (UNCLASSIFIED)
Classification: UNCLASSIFIED
Caveats: NONE
I want to do a T-test on two groups. Group 1 receives a treatment,
group 2 does not.
The standard null hypothesis applies: MU1 = MU2
My alternative hypothesis is MU1 < MU2.
The default alternative in SPSS is MU1 not equal to MU2, and provides 2
sided significance.
Is there a way to specify the strictly less than condition in my
alternative hypothesis?
Steve
Classification: UNCLASSIFIED
Caveats: NONE
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