Date:         Fri, 15 Feb 2008 16:10:48 -0500
Reply-To:     Richard Ristow <wrristow@mindspring.com>
Sender:       "SPSSX(r) Discussion" <SPSSX-L@LISTSERV.UGA.EDU>
From:         Richard Ristow <wrristow@mindspring.com>
Subject:      Re: Computing time spent
Comments: To: ViAnn Beadle <vab88011@gmail.com>
Comments: cc: Sara House <shouse1@luc.edu>
In-Reply-To:  <002a01c87014$08e60bd0$1ab22370$@com>
Content-Type: text/plain; charset="us-ascii"; format=flowed

At 03:47 PM 2/15/2008, ViAnn Beadle wrote:

>Assuming that both are datetime variables you can subtract time2
>from time1 which will give you time in seconds and then you can go
>from there to the correct level of granularity through division.

Exactly. Though, instead of division, I think it gives more readable
code to use the CTIME functions:

CTIME.MINUTES(time2-time1), or CTIME.HOURS(time2.time1), or CTIME.DAYS

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