Date: Tue, 17 Jun 2008 23:37:08 -0600
Reply-To: Richard Read Allen <peakstat@WISPERTEL.NET>
Sender: "SAS(r) Discussion" <SAS-L@LISTSERV.UGA.EDU>
From: Richard Read Allen <peakstat@WISPERTEL.NET>
Subject: Re: Regular expressions
In-Reply-To: <BAY123-W38F99B1CDB326078110480DEAB0@phx.gbl>
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Toby,<br>
<br>
Thanks for the suggestion. This works for these examples however the
problem I'm facing is more complicated than this. I've got a string of
up to 2000 characters with 1s and 0s and need to search the whole
string for each occurrence of 10...01, where the string of 0s is 1 or
more and less than or equal than 31 and replace it with 1X...X1. Can a
regular expression be written to do this?<br>
<br>
<tt>have-
11110000111111000000000000000000000000000000000111111000000000000000000011111111111110111111<br>
want-
1111XXXX111111000000000000000000000000000000000111111XXXXXXXXXXXXXXXXXXX1111111111111X111111<br>
</tt><br>
Thanks,<br>
<br>
Richard<br>
<br>
toby dunn wrote:
<blockquote cite="mid:BAY123-W38F99B1CDB326078110480DEAB0@phx.gbl"
type="cite">
<pre wrap="">Data _Null_ ;
Length X $ 10 ;
Do X = '1' , '10' , '101' , '1001' ,
'10001' , '100001' , '1000001' ;
X = PrxChange( 's/0/X/o' , -1 , Strip(X) ) ;
Put X= ;
End ;
Run ;
Toby Dunn
"Don't bail. The best gold is at the bottom of barrels of crap."
Randy Pausch
"Be prepared. Luck is where preparation meets opportunity."
Randy Pausch
</pre>
<blockquote type="cite">
<pre wrap="">Date: Tue, 17 Jun 2008 22:27:44 -0600
From: <a class="moz-txt-link-abbreviated" href="mailto:peakstat@WISPERTEL.NET">peakstat@WISPERTEL.NET</a>
Subject: Regular expressions
To: <a class="moz-txt-link-abbreviated" href="mailto:SAS-L@LISTSERV.UGA.EDU">SAS-L@LISTSERV.UGA.EDU</a>
I'm new to Perl regular expressions and am trying to create one to
perform the following replacements:
101=1X1
1001=1XX1
10001=1XXX1
etc., replacing up to 31 consecutive "0" with "X". Is this possible?
Thanks,
Richard
</pre>
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