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Date:         Mon, 18 May 2009 04:21:31 -0700
Reply-To:     "Schwarz, Barry A" <barry.a.schwarz@BOEING.COM>
Sender:       "SAS(r) Discussion" <SAS-L@LISTSERV.UGA.EDU>
From:         "Schwarz, Barry A" <barry.a.schwarz@BOEING.COM>
Subject:      Re: Flagging multiple ID's on the same day
In-Reply-To:  <5919cff3-490e-44c5-abf0-17d032bf3484@o27g2000vbd.googlegroups.com>
Content-Type: text/plain; charset="us-ascii"

Your comment would be correct if the expression were (first.ID_B = last.ID_B).

As written, the expression is true only for a group with a single observation.

With a multi-observation group, last.ID_B is 0 for the first observation (rendering the entire expression false) and first.ID_B is 0 for every subsequent observation (also rendering the entire expression false).

-----Original Message----- From: Richard A. DeVenezia Sent: Monday, May 11, 2009 5:21 AM To: SAS-L@LISTSERV.UGA.EDU Subject: Re: Flagging multiple ID's on the same day

snip

Additionally, (first.ID_B and last.ID_B) is an insufficient test

(first.ID_B and last.ID_B) will test true in two different situations - single observation in group (flags are both 1) - more than 2 observations in group, and at an 'internal' observation (flags are both 0)


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