Date: Fri, 12 Jun 2009 13:37:32 -0400
Reply-To: "Handel, Richard W." <HandelRW@EVMS.EDU>
Sender: "SPSSX(r) Discussion" <SPSSX-L@LISTSERV.UGA.EDU>
From: "Handel, Richard W." <HandelRW@EVMS.EDU>
Subject: Re: ranking syntax
In-Reply-To: A<C8F106C585464D9BA08582E7DA160032@ssw.buffalo.edu>
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Gene,
Thanks. I found syntax on raynald's site that ranks within cases. It
was easy to modify it to do what I want. Thanks again.
Rick
Richard W. Handel, Ph.D.
Associate Professor
Department of Psychiatry and Behavioral Sciences
Eastern Virginia Medical School
825 Fairfax Avenue, Hofheimer Hall
Norfolk, VA 23507
Phone (757)-446-7992
-----Original Message-----
From: SPSSX(r) Discussion [mailto:SPSSX-L@LISTSERV.UGA.EDU] On Behalf Of
Gene Maguin
Sent: Friday, June 12, 2009 1:31 PM
To: SPSSX-L@LISTSERV.UGA.EDU
Subject: Re: ranking syntax
Richard,
A realy simple way to do this, provided you don't have too many cases,
and
even then, I'd guess, it could be done in stages, is use the Flip
command to
flip the dataset so that variables are now rows and subjects are now
columns
(and, thus, variables). Next, use the Rank command to rank the
variables.
Finally, use the Flip command again to restore the dataset to its
original
structure. I haven't done this in a long time but I'll bet others have
and
can comment. Try this out and see if it will work for you. Post back and
let
us know.
The alternative is to write syntax to do a within cases sort and while
that
is not too hard, accounting for ties and for missing data makes the code
complex.
Gene Maguin
>>1) Take 10 variables (x1 to x10) that have integer values between 30
and
100.
2) Create syntax that rank orders these variables and writes them out to
a
second set of variables based on rank order (in ascending order). In
other
words, the second set of variables would indicate the relative standing
of
each case (X1 to X10). (Let's say the second set of variables is named
X1a
to X10a.)
So, it would end up like this (I will limit it to 3 variables for this
example):
Input data:
X1 = 50
X2 = 70
X3 = 55
New Variable:
X1a = 1
X2a = 3
X3a = 2.
The more complicated issue is that a tie needs to be assigned a
mid-point
value. So, if
Input data:
X1 = 50
X2 = 50
X3 = 70
Then,
X1a = 1.5
X2a = 1.5
X3a = 3
(That is, X3 is still the third highest score.)
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