Date: Mon, 6 Jul 2009 04:26:39 -0700
Reply-To: Bruce Weaver <bweaver@lakeheadu.ca>
Sender: "SPSSX(r) Discussion" <SPSSX-L@LISTSERV.UGA.EDU>
From: Bruce Weaver <bweaver@lakeheadu.ca>
Subject: Re: Testing the significant difference in Proportions
In-Reply-To: <818763.37611.qm@web112613.mail.gq1.yahoo.com>
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Jims More wrote:
>
> I have two categorical variables. One is the response variable, a yes/no
> variable. The other is a categorical predictor variable which has 5
> categories. The proportion table of the gathered data (n=5000) looks like
> as follows:
> Â
>                         Row % of Yes Response          Row % of No
> Response
> Category1Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â .40Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â .60
> Category2Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â .30Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â .70
> Category3Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â .80Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 20
> Category4Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â .40Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â .60
> Category5Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â .34Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â .66
> Â
> How to test using SPSSÂ if the proportions of Yes and No are significantly
> equal for each category?
> Â
> Thank you for any help.
> Jims
>
You can always roll your own, like this:
data list list / cat (f2.0) x N (2f6.0).
begin data
1 40 100
2 30 100
3 80 100
4 40 100
5 34 100
end data.
compute p = x/N.
compute se = SQRT( p*(1-p)/N).
compute z = (p - .5)/se.
compute pvalue = 2*(1-(CDF.NORMAL(abs(z),0,1))) .
format se pvalue (f5.3).
list.
You'll have to fill in the correct values of X and N, of course.
-----
--
Bruce Weaver
bweaver@lakeheadu.ca
http://sites.google.com/a/lakeheadu.ca/bweaver/
"When all else fails, RTFM."
--
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