| Date: | Thu, 29 Oct 2009 09:06:08 -0700 |
| Reply-To: | Arthur Burke <Art.Burke@EDUCATIONNORTHWEST.ORG> |
| Sender: | "SPSSX(r) Discussion" <SPSSX-L@LISTSERV.UGA.EDU> |
| From: | Arthur Burke <Art.Burke@EDUCATIONNORTHWEST.ORG> |
| Subject: | Re: how to compute this? |
|
| In-Reply-To: | A<200910280230.n9RJW5vB008058@malibu.cc.uga.edu> |
| Content-Type: | text/plain; charset="US-ASCII" |
For details of how SPSS does the t-test, try ...
/Help/Statistics Coach/Compare Groups for Significant Differences/ ...
/T Test Algorithms
Art
*************************
Art Burke
Associate, Evaluation Program
Education Northwest
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-----Original Message-----
From: Wang Xu [mailto:dachengruoque@163.COM]
Sent: Tuesday, October 27, 2009 7:30 PM
To: SPSSX-L@LISTSERV.UGA.EDU
Subject: how to compute this?
Hi all list members,
I am a green hand at data analysis. Recently I was bumped by a
scenario presented in a paper by Roger Kirk Kirk, R. E. (1996).
Practical Significance: A Concept Whose Time Has Come.
Educational and Psychological Measurement, 56(5), 746-759.
on the page 755 of the paper the 2nd paragraph there is it. The summary
of the scenario is as follows,
13 patients were assigned evenly to control and experimental
groups.t(10) =1.61, p=.14, the mean for experimetal group is 13 IQ
points higher than that of control group. At the end of the paragraph
the author said that a 95% confidence interval for the population mean
difference is likely to be between -6.3 and 32.3 IQ points. Do all the
present conditions necessiate the computation of confidence interval for
the population mean difference?
I thought that there should be one more condition: standard deviation.
Am I right? In spss there is always some computation of confidence
interval for the population mean difference? How is it computed ? What
is the formla for computing this? Thanks a lot!
W.X.
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