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Date:         Wed, 23 Dec 2009 14:53:53 -0500
Reply-To:     Jeff <zhujp98@GMAIL.COM>
Sender:       "SAS(r) Discussion" <SAS-L@LISTSERV.UGA.EDU>
From:         Jeff <zhujp98@GMAIL.COM>
Subject:      Re: how to test the signicanace
Comments: To: Ted Clay <>
In-Reply-To:  <004601ca83fa$4bf328d0$e3d97a70$@net>
Content-Type: text/plain; charset=ISO-8859-1

Thanks. Is it possible to do a binomial proposion test to G1 and G2 and how? Thanks, Jeff

On Wed, Dec 23, 2009 at 1:03 PM, Ted Clay <> wrote:

> * I think this might help. One way to do this is to create a data set with > the 4 cells of a 2-by-2 table, and let PROC FREQ do the test of > significance. > The key is the "WEIGHT" statement in PROC FREQ. > ; > Data ready; > Group=1; admitted='Yes'; Num=Y1; output; > Group=1; admitted='No '; Num=X1-Y1; output; > Group=2; admitted='Yes'; Num=Y2; output; > Group=2; admitted='No '; Num=X2-Y2; output; > Run; > > Proc freq data=ready; > Table group*admitted; > Weight Num; > Run; > > You will get a Chi-square test by default. > A 2-tailed Fisher's exact test would be my choice of test, which requires > adding "/exact". > You might also be interested in relative risk statistics and confidence > intervals, which requires you to pay close attention to which is "row 1" > and > "column 1". > > TC > > > > > -----Original Message----- > From: SAS(r) Discussion [mailto:SAS-L@LISTSERV.UGA.EDU] On Behalf Of Jeff > Sent: Wednesday, December 23, 2009 6:55 AM > To: SAS-L@LISTSERV.UGA.EDU > Subject: how to test the signicanace > > Two group of people. all people in G1 is in a health plan, and these in G2 > is not > G1 have x1 member, and y1 hospital admits. hospital admit rate is > hr1=y1/x1 > G2 has x2 member and y1 hospital admits. hospital admit rate is h21=y2/x2 > > I want to test if there is significant difference between G1 and G2. > What kind test should I use? > > Thanks. > JP > > >

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