LISTSERV at the University of Georgia
Menubar Imagemap
Home Browse Manage Request Manuals Register
Previous messageNext messagePrevious in topicNext in topicPrevious by same authorNext by same authorPrevious page (May 2011, week 3)Back to main SAS-L pageJoin or leave SAS-L (or change settings)ReplyPost a new messageSearchProportional fontNon-proportional font
Date:         Fri, 20 May 2011 11:59:56 -0500
Reply-To:     Joe Matise <snoopy369@GMAIL.COM>
Sender:       "SAS(r) Discussion" <SAS-L@LISTSERV.UGA.EDU>
From:         Joe Matise <snoopy369@GMAIL.COM>
Subject:      Re: Patients who are in either of three tables
Comments: To: Irin later <irinfigvam@yahoo.com>
In-Reply-To:  <47557.51450.qm@web39422.mail.mud.yahoo.com>
Content-Type: text/plain; charset=ISO-8859-1

What output do you need? Just the patient id? Everything?

Something like this would accomplish something like what you want, I would think:

proc sql; create table d as select * from ( select * from a full outer join b on a.patientid=b.patientid) ab full outer join c on ab.patientid=c.patientid ); quit;

You can manipulate the select * to get what you need.

-Joe

On Fri, May 20, 2011 at 11:53 AM, Irin later <irinfigvam@yahoo.com> wrote:

> I am trying to get patients who are either in table1 or Table 2 or Table3. > Should be not complicated ...but I am kind of confused at the end of Friday > as it is a kind of an urgent matter... > I have patients' id s, flag and program fields. > > How Can I implement it with code? I do not have any duplicats in either > table. > > Could you please help me with that? Thank you in advance, > > Irin >


Back to: Top of message | Previous page | Main SAS-L page