Date: Thu, 9 Jun 2011 16:51:14 -0700
Reply-To: "Parise, Carol A." <PariseC@sutterhealth.org>
Sender: "SPSSX(r) Discussion" <SPSSX-L@LISTSERV.UGA.EDU>
From: "Parise, Carol A." <PariseC@sutterhealth.org>
Subject: Re: automate computations
In-Reply-To: <1307496464627-4463647.post@n5.nabble.com>
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David,
>I'm not sure how this achieves the stated goal of "grouping" people.
Point well taken and thank you for the code. Once i run this, my plan was again to use a bunch of compute statements to find all of the people who did the same task in the same year.
I would love it if you or someone had a more elegant solution. Maybe one that doesn't require flattening the file?
Thanks
Carol
-----Original Message-----
From: SPSSX(r) Discussion [mailto:SPSSX-L@LISTSERV.UGA.EDU] On Behalf Of David Marso
Sent: Tuesday, June 07, 2011 6:28 PM
To: SPSSX-L@LISTSERV.UGA.EDU
Subject: Re: automate computations
"create a compute for every permutation of year/task! "
...
First of all, forget about explicitly computing every combination.
Use VECTORS and a simple compute as follows:
NUMERIC Task01_1974 TO Task01_2010 Task02_1974 TO Task02_2010 ............
.. etc ....... TASK28_1974 TO Task28_2010.
RECODE Task01_1974 TO Task28_2010 (ELSE=0).
VECTOR TaskYear=Task01_1974 TO Task28_2010.
COMPUTE TaskYear( (Task-1) * 36 + Year - 1974 + 1) =1.
"I suspect there may be a more efficient method to group people who have done the same tasks in the same year and if anyone has one, I thank you in advanced."
I'm not sure how this achieves the stated goal of "grouping" people.
HTH, but I'm not sure it does ;-)
David
------
Parise, Carol A. wrote:
>
> Hi all,
>
> This is another question about the same data that i asked about a few
> weeks agoin in the question: "CasesToVars or better idea". Marta
> provided some syntax to flip the file which worked great. The next
> goal is to identify the people who performed the same tasks in the
> same year and compare their time on the tasks. When i flattened the
> file, i started creating a bunch of computes:
>
> compute TaskOne_1986 = 0.
> if (Year =1986 and Task = 1) TaskOne_1986=1.
>
> etc.
>
> then planned to do another set of computes: If TaskOne_1986=1 and
> TaskOne_1987=1 and TaskOne=1990 etc to find groups of people who did a
> particular task in a particular year. After a few rounds of "computes"
> i started wondering of there was a more automated way to do this.
>
> i went back to the "long file" format (my data look like this):
> ID Year Task Time Age
> 1 1986 ONE 2:15 40
> 1 1990 ONE 3:00 44
> 1 2000 ONE 1:59 45
> 1 2005 TWO 4:05 50
> 1 2007 TWO 3:58 52
> 1 2008 TWO 3:42 53
> 2 2001 TWO 3:00 30
> 2 2002 THREE 1:35 31
> 2 2003 THREE 1:55 33
> 2 2005 TWO 2:25 35
> 2 2006 THREE 2:40 36
>
> ...and ran a task by year crosstabulation table. Here is an example of
> the results of this file.
>
> <SNIP TABLE>
>
> There are a total of 28 tasks performed over 36 (1974-2010) years.
> Using my current strategy means i would need to create a compute for
> every permutation of year/task! I also need to know the age of people
> in the year that they performed the task. I ultimately plan to use
> linear mixed models so i don't need to flatten the file.
>
> I suspect there may be a more efficient method to group people who
> have done the same tasks in the same year and if anyone has one, I
> thank you in advanced.
>
> Carol
>
--
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