| Date: | Wed, 21 Sep 2011 10:43:22 -0700 |
| Reply-To: | "Adams, Nicholas" <NRAdams@CVTY.COM> |
| Sender: | "SAS(r) Discussion" <SAS-L@LISTSERV.UGA.EDU> |
| From: | "Adams, Nicholas" <NRAdams@CVTY.COM> |
| Subject: | Re: Join function |
| In-Reply-To: | <CAM+YpE8UvMM1FiX9U1cniFZddjTciQafZkagCBhHEkvKm09dGg@mail.gmail.com> |
| Content-Type: | text/plain; charset="us-ascii" |
I think you are close Joe, but i accidentally left out one other
scenario that this needs to accomodate.
v43.12 join to v43.12
I think converting these to numbers caused errors with the alpha based
codes.
Any other work around?
-----Original Message-----
From: SAS(r) Discussion [mailto:SAS-L@LISTSERV.UGA.EDU] On Behalf Of Joe
Matise
Sent: Wednesday, September 21, 2011 12:51 PM
To: SAS-L@LISTSERV.UGA.EDU
Subject: Re: Join function
You mean join records that have 170.0 to 170?
proc sql;
create table c as
select * from a,b
where input(a,BEST12.) = input(b,BEST12.); quit;
should work... just convert them to numbers on the fly.
-Joe
On Wed, Sep 21, 2011 at 11:24 AM, Adams, Nicholas <NRAdams@cvty.com>
wrote:
> Is there a function I can use in Proc SQL that will allow me to join
> these character values together? I think I need something to get rid
> of any trailing or leading zeros.
>
> 170.0 join to 170
> 041.12 join to 41.12
> 363.40 join to 363.4
>
>
> Thank you!
>
> Nick
>
>
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Email Confidentiality Notice: The information contained in this transmission is confidential, proprietary or privileged and may be subject to protection under the law, including the Health Insurance Portability and Accountability Act (HIPAA).
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