Date:         Wed, 7 Dec 2011 13:07:30 -0500
Reply-To:     "Bian, Haikuo" <HBian@FLQIO.SDPS.ORG>
Sender:       "SAS(r) Discussion" <SAS-L@LISTSERV.UGA.EDU>
From:         "Bian, Haikuo" <HBian@FLQIO.SDPS.ORG>
Subject:      Re: Using Min and Max Values of a Single Variable To Create a New
              Variable
Comments: To: R B <ryan.andrew.black@GMAIL.COM>
In-Reply-To:  <CAMMWLD1gcA3X=wRgNgaSaDj4SC0VRK64r-hhh3pbsm5Hm2=goQ@mail.gmail.com>
Content-Type: text/plain; charset="us-ascii"

Obviously like Toby has showed, SQL is the native tool for this task. Just in case you are wondering how this could be done using datastep, here is one approach:

data have;
infile cards;
input x1;
cards;
1
4
23
41
-3
0
;

data need (drop=_:);
retain _min _max;
  do until (last);
     set have end=last;
     _min=min(_min, x1);
         _max=max(_max, x1);
  end;

  do until (last1);
     set have end=last1;
     x1_normalized=( X1 - _min ) / ( _max - _Min);
         output;
  end;
run;

proc print;run;

Kindly Regards,
Haikuo

-----Original Message-----
From: SAS(r) Discussion [mailto:SAS-L@LISTSERV.UGA.EDU] On Behalf Of R B
Sent: Tuesday, December 06, 2011 7:20 PM
To: SAS-L@LISTSERV.UGA.EDU
Subject: Re: Using Min and Max Values of a Single Variable To Create a New Variable

Perfect! Thanks!

On Tue, Dec 6, 2011 at 6:59 PM, toby dunn <tobydunn@hotmail.com> wrote:

> Proc SQL ;
> Create Tale Need As
>  Select * , ( ( X1 - Min( X1 ) ) / ( Max( X1 ) - Min( X1 ) ) ) As
>  x1_normalized
>   From Have ;
> Quit ;
>
>
>
> Toby Dunn
>
>
> If you get thrown from a horse, you have to get up and get back on, unless
> you landed on a cactus; then you have to roll around and scream in pain.
>
> "Any idiot can face a crisis-it's day to day living that wears you out"
> ~ Anton Chekhov
>
>
>
> > Date: Tue, 6 Dec 2011 18:51:28 -0500
> > From: ryan.andrew.black@GMAIL.COM
> > Subject: Using Min and Max Values of a Single Variable To Create a New
> Variable
> > To: SAS-L@LISTSERV.UGA.EDU
> >
> > Hi,
> >
> > My dataset is structured as:
> >
> > x1
> > --
> > 1
> > 4
> > 23
> > 41
> > -3
> > 0
> >
> > Note that 41 is the maximum value and -3 is the minimum value.
> >
> > Within a datastep, I'd like to compute the values for a new variable,
> > "x1_normalized", using the following equation:
> >
> > x1_normalized = [x1 - (minimum value of x1)] / [(maximum value of x1) -
> > (minimum value of x1)]
> >
> > So, the value of the first case for "x1_normalized" would be:
> >
> > (1 - (-3)) / (41 - (-3)) = 4 / 44 = .090909090909
> >
> > The value of the second case for "x1_normalized" would be:
> >
> > (4 - (-3)) / (41 - (-3)) = 7 / 44 = .15909090909
> >
> > My new dataset should look like this:
> >
> > x1 x1_normalized
> > -- --------------------
> > 1 .090909090909
> > 4 .159090909090
> > 23 etc.
> > 41 etc.
> > -3 etc.
> > 0 etc.
> >
> > The MIN and MAX functions do not seem appropriate for what I'm trying to
> do
> > here.
> >
> > Any ideas?
> >
> > Thanks,
> >
> > Ryan
>
>
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