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Date:         Wed, 24 Sep 1997 16:32:11 -0500
Reply-To:     "Nichols, David" <nichols@SPSS.COM>
Sender:       "SPSSX(r) Discussion" <SPSSX-L@UGA.CC.UGA.EDU>
From:         "Nichols, David" <nichols@SPSS.COM>
Subject:      Re: NLR, Poisson, and help!!
Comments: To: Dale Glaser <dale.glaser@SHARP.COM>

Fitting a linear model to transformed data and then back- transforming the resulting coefficients doesn't give you the same results as fitting the nonlinear model directly.

David Nichols Senior Support Statistician SPSS Inc. nichols@spss.com

>---------- >From: Dale Glaser[SMTP:dale.glaser@SHARP.COM] >Sent: Wednesday, September 17, 1997 1:19 PM >To: SPSSX-L@UGA.CC.UGA.EDU >Subject: NLR, Poisson, and help!! > >two part question and any help would be most appreciated: > >1) > >Analyzing a variable (consisting of counts) called number of >readmissions: > >breakdown is as follows: > >value frequency >0 55 >1 25 >2 10 >3 4 >4 1 >5 1 > >.......per Neter, et al , Applied Linear Statistical Models, this variable >seems to follow a poisson distribution, in that the "outcomes are >counts....with a large number of occurrences being a rare event" (p. >609)......in the context of comparing an intervention vs control group on >number of readmissions, and the attendant violation of assumptions (e.g., >normality) parametric statistics (e.g., oneway ANOVA) seems >inappropriate, thus, one alternative is the nonparametric analogue (e.g., >Mann-Whitney) or possibly dichotmize the variable (0-no readmit; 1 >-readmit) and conduct logistic regression.....however, my brief perusal of >nonlinear regression seems to indicate that this option may be the most >appropriate analytical avenue?........so, for this type of data is NLR >appropriate? overkill? inappropriate?...any suggestions greatly >appreciated..... > > >2) deciding to practice NLR, using some data from Neter et al (pg. 536), >they use days hospitalized to predict prognostic index.........a log >transform of the criterion variable was conducted and then they used >OLS to obtain the following solution: y'= 4.0371 + -.03797; in their >example they use the following start values: > >G0 = exp(4.0371) = 56.6646 >G1 = -.03797 > >they use the following prediction formula: > >f (X, G)= (56.6646)exp[-.03797(2)] > >......so, I used the following syntax: > >* NonLinear Regression. >MODEL PROGRAM G0=56.665 G1=-.0380 . >COMPUTE PRED_ = G0*exp(G1*2). >NLR logprog > /OUTFILE='C:\WINDOWS\TEMP\SPSSFNLR.TMP' > /PRED PRED_ > /SAVE PRED RESID DERIVATIVES > /CRITERIA SSCONVERGENCE 1E-8 PCON 1E-8 . > > >...and got nothing close to their results on page 545!!!.....five model >iterations resulted in the following: Y' = 4048.95 + -35.73(X) >........(their >final result is: Y' = (58.6065)exp(-.03959X) > >............so encountering a domain that I am admittedly a complete >neophyte, what do most of you do when encountering an analyses >where there is an abundance of 0 values?..........if you use NLR, do you >use coefficients from the regression equation as your starting values? > >thank you!! > >Dale Glaser, Ph.D. >Clinical Outcomes Research/Dept. of Psychology >Sharp HealthCare/SDSU >San Diego, CA >


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