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Date:         Tue, 27 Jan 1998 12:11:02 -0500
Reply-To:     Carlos Garces <Carlos_Garces@IVAX.COM>
Sender:       "SAS(r) Discussion" <SAS-L@UGA.CC.UGA.EDU>
From:         Carlos Garces <Carlos_Garces@IVAX.COM>
Content-type: text/plain; charset=us-ascii

Dear SAS-L experts,

I don't know what is happening, but maybe some of the SAS gurus could help me out. I've simplified the code so it is easier to follow:

%MACRO HARDCODE(ID,VARIABLE,OLDVAL,NEWVAL); IF PAT=&ID AND &VARIABLE=&OLDVAL THEN DO; PUT 'PREVIOUS ' PAT= &VARIABLE=; &VARIABLE=&NEWVAL; PUT 'NEW VALUE ' PAT= &VARIABLE=; END; ELSE IF PAT=&ID THEN DO; PUT "CONDITION FOR " PAT= " NOT MET - OLD VALUE: &OLDVAL - CURRENT VALUE: " &VARIABLE=; END; %MEND;

data pistart; do pat=630 to 640; output; end;

data temp; do pat=865 to 882; update='27JAN98'D; output; FORMAT UPDATE MMDDYY8.; end;

data pistart; set pistart temp; %HARDCODE(635,update,.,'27jan98'd); run;

If you see the output below, you will notice that the value for variable UPDATE is retained!

This doesn't happen if I use a 'by pat' statement. I also cannot replicate this situation if I use an IF statement instead of the macro.

proc print data=pistart; run;

OBS PAT UPDATE

1 630 . 2 631 . 3 632 . 4 633 . 5 634 . 6 635 01/27/98 7 636 01/27/98 8 637 01/27/98 9 638 01/27/98 10 639 01/27/98 11 640 01/27/98 12 865 01/27/98 13 866 01/27/98 14 867 01/27/98 15 868 01/27/98 16 869 01/27/98 17 870 01/27/98 18 871 01/27/98 19 872 01/27/98 20 873 01/27/98 21 874 01/27/98 22 875 01/27/98 23 876 01/27/98 24 877 01/27/98 25 878 01/27/98 26 879 01/27/98 27 880 01/27/98 28 881 01/27/98 29 882 01/27/98


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