Date:         Wed, 28 Jan 1998 11:51:37 -0600
Reply-To:     txplltw@UABCVSR.CVSR.UAB.EDU
Sender:       "SAS(r) Discussion" <SAS-L@UGA.CC.UGA.EDU>
From:         Todd Weiss <txplltw@UABCVSR.CVSR.UAB.EDU>
Subject:      Re: COUNT function in SAS
Comments: To: Soumen Mukherjee <SMukherjee@MAPSNET.COM>
In-Reply-To:  <9801281709.AA23781@UABCVSR.cvsr.uab.edu>
Content-Type: TEXT/PLAIN; charset=US-ASCII

Hi Soumen,
 
   There are other ways to do this, but the following
should work.
 
Regards,
 
Todd Weiss
 
__________________________________________________________________
 
%let arg = 1;  *Use whatever numeric argument you want;
 
data test ( keep = x1 - x5 cnt );
     array x ( 5 );
     array tf ( 5 );
input x1 - x5;
     do i = 1 to dim ( x );
        tf ( i ) = x ( i ) = &arg;
     end;
     cnt = sum ( of tf1 - tf5 );
 
datalines;
1 2 3 1 1
1 4 3 2 1
2 3 1 2 4
;
 
proc print;
run;
 
 
 
On Wed, 28 Jan 1998, Soumen Mukherjee wrote:
 
> Is there a function in SAS that will count the number of arguments that
> match a specified value? For example lets say:
>
> x1 = 1
> x2 = 3
> x3 = 4
> x4 = 1
> x5 = 2
>
> Then a "count" function like
>
> result = count (of x1-x5, 1);
>
>  should return a value of 2 for result.
>
> Thanks in advance for any help.
>
> Soumen.
>