|Date: ||Wed, 12 May 1999 10:17:50 +0100|
|Reply-To: ||tra <tra@PROTEUS.CO.UK>|
|Sender: ||"SAS(r) Discussion" <SAS-L@UGA.CC.UGA.EDU>|
|From: ||tra <tra@PROTEUS.CO.UK>|
|Organization: ||Proteus Molecular Design Ltd|
|Subject: ||Re: Maximum likelihood estimation|
|Content-Type: ||text/plain; charset=us-ascii|
If theta is known, then median = theta/sqrt(2).
I presume theta is unknown, and you need to estimate from a set of data x_i :
The mle of theta is the smallest possible value, given x:
mle(median) = max(x)/sqrt(2)
John Ward wrote:
> I have a question, please.
> I want to find the maximum likelihood estimate for the median of the
> distribution. I would really appreciate it if you could give me some help.
> f(x)=2x/theta**2 , 0<x<theta
> =0, otherwise.
> Thank you
> John Ward
> New Jersey
> Get Free Email and Do More On The Web. Visit http://www.msn.com
T R Auton PhD MSc C.Math
Head of Biomedical Statistics
Proteus Molecular Design Ltd
Lyme Green Business Park
Cheshire SK11 0JL